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ID:
Class: 12
Subject: Math
Topic: Application of Derivative
Type: Short
Question:
Find the absolute maximum and minimum values of the function \( f(x) = x^3 \) in the interval \([ -2, 2 ]\).
Official Solution
Explanation:
We have \( f(x) = x^3 \)
\[
f'(x) = 3x^2
\]
Setting \( f'(x) = 0 \Rightarrow x = 0 \)
Now evaluate \( f \) at endpoints and critical points:
\[
f(-2) = (-2)^3 = -8 \\
f(0) = 0 \\
f(2) = 2^3 = 8
\]
\(\textbf{Absolute maximum}\) is \( f(2) = 8 \) at \( x = 2 \) and
\(\textbf{Absolute minimum}\) is \( f(-2) = -8 \) at \( x = -2 \)
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