ID: Class: 12Subject: MathTopic: Application of DerivativeType: McqYear: 2025
Question:
A cylindrical tank of radius \(10\) cm is being filled with sugar at the rate of \(100~\pi~cm^{3}/s\). The rate, at which the height of the sugar inside the tank is increasing, is:
A. \(0.1~cm/s\)
B. \(0.5~cm/s\)
C. \(1~cm/s\)
D. \(1.1~cm/s\)
Official Solution
Correct Answer: \(1~cm/s\)
Explanation:
The rate at which the height of sugar inside the cylindrical tank increases can be determined using the formula for the volume of a cylinder:
\(V = \pi r^2 h\)
Given:
Radius, \(r = 10 \text{ cm}\)
Rate of change of volume, \(\dfrac{dV}{dt} = 100\pi \text{ cm}^3/\text{s}\)
Since the radius remains constant, differentiate both sides of the volume equation with respect to time \(t\):
\(\dfrac{dV}{dt} = \pi r^2 \dfrac{dh}{dt}\)
Substitute the known values:
\(100\pi = \pi (10)^2 \dfrac{dh}{dt}\)
\(100\pi = 100\pi \dfrac{dh}{dt}\)
Dividing both sides by \(100\pi\):
\(\dfrac{dh}{dt} = 1 \text{ cm/s}\)
Therefore, the height of the sugar in the tank is increasing at a rate of \(1 \text{ cm/s}\).
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