ID: Class: 12Subject: MathTopic: Application of DerivativeType: Short
Question:
Find the maximum and minimum values, if any, of the function
\(
f(x) = (2x - 1)^2 + 3
\)
Official Solution
Explanation:
We have:
\[
(2x - 1)^2 \geq 0 \text{ for all } x \in \mathbb{R}
\]
\[
f(x) = (2x - 1)^2 + 3 \geq 3 \text{ for all } x \in \mathbb{R}
\]
Minimum value occurs when \(2x - 1 = 0 \Rightarrow x = \frac{1}{2}\).
\[
\text{Minimum value of } f\left(\frac{1}{2}\right) = (2 \cdot \frac{1}{2} - 1)^2 + 3 = 3
\]
No maximum value exists since the function is unbounded above.
AI Teacher
Disclaimer: AI-generated content may contain errors. Please verify with standard textbooks.