ID: Class: 12Subject: MathTopic: Application of DerivativeType: Short
Question:
The total revenue in Rupees received from the sale of \(x\) units of a product is given by \(R(x) = 13{x^2} + 26x + 15\). Find the marginal revenue when \(x = 7\).
Official Solution
Explanation:
The total revenue (in rupees) from selling \(x\) units of a product is given by:
\[R(x) = 13x^2 + 26x + 15\]
We are asked to find the marginal revenue when \(x = 7\).\[\]
Marginal revenue is the rate of change of total revenue with respect to the number of units sold, i.e.,
\(MR = \dfrac{dR}{dx}\)
\[\]
Differentiate \(R(x)\):
\[\dfrac{dR}{dx} = 13 \cdot 2x + 26 = 26x + 26\]
Now substitute \(x = 7\):
\[MR = 26 \cdot 7 + 26 = 182 + 26 = 208\]
Final Answer:
The marginal revenue when \(x = 7\) is Rs. 208
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