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ID:
Class: 12
Subject: Math
Topic: Application of Derivative
Type: Short
Question:
Find the local maxima and minima of \( g(x) = \frac{1}{x^2 + 2} \).
Official Solution
Explanation:
\[
g'(x) = \frac{-2x}{(x^2 + 2)^2}
\Rightarrow g'(x) = 0 \Rightarrow x = 0
\]
Check sign change:
- For \( x < 0 \), \( g'(x) > 0 \)
- For \( x > 0 \), \( g'(x) < 0 \)
So by first derivative test:
\[
x = 0 \text{ is a local maximum}
\Rightarrow g(0) = \frac{1}{2}
\]
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