ID: Class: 12Subject: MathTopic: Application of DerivativeType: Short
Question:
The total cost \(C(x)\) in Rupees associated with the production of \(x\) units of an item is given by \(C(x) = 0.007{x^3} - 0.003{x^2} + 15x + 4000\). Find the marginal cost when 17 units are produced.
Official Solution
Explanation:
The total cost \(C(x)\) (in rupees) for producing \(x\) units of an item is given by:
\[C(x) = 0.007x^3 - 0.003x^2 + 15x + 4000\]
We are asked to find the marginal cost when \(x = 17\).\[\]
Marginal cost is the rate of change of total cost with respect to the number of units produced, i.e.,