ID: Class: 12Subject: MathTopic: Application of DerivativeType: Short
Question:
Find the maximum and minimum values of the function
\(
g(x) = -|x + 1| + 3
\)
Official Solution
Explanation:
Since \(-|x + 1| \leq 0\),
\[
g(x) = -|x + 1| + 3 \leq 3
\]
Equality occurs when \(|x + 1| = 0 \Rightarrow x = -1\).
\[
\text{Maximum value of } g = g(-1) = -| -1 + 1 | + 3 = 3
\]
There is no minimum value since \(-|x + 1|\) decreases without bound.
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