QPaperGen

Since \(|x + 2| \geq 0\) for all \(x \in \mathbb{R}\),
\[
f(x) = |x + 2| - 1 \geq -1
\]
Equality occurs when \(|x + 2| = 0 \Rightarrow x = -2\).
\[
\text{Minimum value of } f = f(-2) = | -2 + 2 | - 1 = -1
\]
There is no maximum value since \(|x + 2|\) grows unbounded as \(x \to \infty\).