ID: Class: 12Subject: MathTopic: Application of DerivativeType: Short
Question:
Prove that the function \( g(x) = \log x \) does not have any maximum or minimum.
Official Solution
Explanation:
We have,
\[
g(x) = \log x \Rightarrow g'(x) = \frac{1}{x}
\]
The function \( \log x \) is defined for \( x > 0 \), and for all such \( x \),
\[
g'(x) = \frac{1}{x} > 0
\]
So, \( g(x) \) is strictly increasing and \( g'(x) \neq 0 \) for any \( x > 0 \).
Therefore, there does not exist any \( c \in (0, \infty) \) such that \( g'(c) = 0 \).
Hence, the function \( g(x) = \log x \) does not have any maximum or minimum.
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