ID: Class: 12 Subject: Math Topic: Continuity and Differentiability Type: Mcq Year: 2024

Question:

For what value of k, the function given below is continuous at \(x=0\) ? \(f(x)=\begin{cases}\frac{\sqrt{4+x}-2}{x},&x\ne0\\ k,&x=0\end{cases}\)
  • A. 0
  • B. \(\frac{1}{4}\)
  • C. 1
  • D. 4