Assertion (A) :\(f(x) = \begin{cases} 3x-8, & x \le 5 \\ 2k, & x > 5 \end{cases}\) is continuous at \(x = 5\) for \(k = \dfrac{5}{2}\).
Reason (R) : For a function \(f\) to be continuous at \(x=a\), \(\lim_{x \to a^-} f(x) = \lim_{x \to a^+} f(x) = f(a)\).