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ID:
Class: 12
Subject: Math
Topic: Continuity and Differentiability
Type: Mcq
Year: 2025
Question:
If \(f(x)=\begin{cases}\frac{\log(1+ax)+\log(1-bx)}{x},&for~x\ne0\\ k&,for~x=0\end{cases}\) is continuous at \(x=0\), then the value of k is:
A.
a
B.
\(a+b\)
C.
\(a-b\)
D.
b
Official Solution
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