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ID:
Class: 12
Subject: Math
Topic: Continuity and Differentiability
Type: Mcq
Year: 2025
Question:
If \(f(x)=\begin{cases}\frac{\sin^{2}ax}{x^{2}},&x\ne0\\ 1,&x=0\end{cases}\) is continuous at \(x=0\), then the value of a is:
A.
1
B.
-1
C.
\(\pm1\)
D.
0
Official Solution
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