QPaperGen

Let’s first think of possible placements:

If P is in position 1, S will be in 6th place.

If P is in 2, S will be in 7th, and so on.

So positions for P–S with 4 letters between them can occur 7 ways (from 1–6, 2–7, …, 7–12).
But since S can come before P as well, total ways to place the pair:

7×2=14 possible position pairs


Now, fixing P and S, we have 10 letters remaining (E, R, M, U, T, A, T, I, O, N), which can be arranged:

\(\dfrac{10!}{2!}=1,814,400\)


Thus, total arrangements:

14×1,814,400=25,401,600