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ID:
Class: 11
Subject: Math
Topic: Permutation
Type: Long
Question:
How many numbers lying between 100 and 1000 can be formed with the digits 0, 1, 2, 3, 4, 5, if the repetition of the digits is not allowed?
Official Solution
Explanation:
The required number\(= {}^{6}P_{3} - {}^{5}P_{2} = \frac{6!}{3!} - \frac{5!}{3!}
= 4 \times 5 \times 6 - 4 \times 5 = 100\)
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