Find the number of arrangements of the letters of the word
INDEPENDENCE so that the vowels never occur together.
Official Solution
Explanation:
The required number of arrangements
= the total number of arrangements (without any restriction) – the number
of arrangements where all the vowels occur together
=\( \frac{12!}{3! 4! 2!}-\frac{8!5!}{3! 2! 4!}== 1663200 – 16800 = 1646400\)
AI Teacher
Disclaimer: AI-generated content may contain errors. Please verify with standard textbooks.