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As \(\text{18}{{\text{0}}^{\text{o}}}\text{= }\!\!\pi\!\!\text{ }\) radian Therefore \({{1}^{\circ }}=\dfrac{\pi }{180}\) radian hence, \(\text{2}{{\text{5}}^{\text{o}}}\text{=}\dfrac{\text{ }\!\!\pi\!\!\text{ }}{\text{180}}\text{ }\!\!\times\!\!\text{ 25}\) radian \(\text{=}\dfrac{\text{5 }\!\!\pi\!\!\text{ }}{\text{36}}\)radian