ID: Class: 12Subject: MathTopic: Application of IntegralsType: McqYear: 2025
Question:
The area of the region enclosed by the curve \(y=\sqrt{x}\) and the lines \(x=0\) and \(x=4\) and x-axis is:
A. \(\frac{16}{9}\) sq. units
B. \(\frac{32}{9}\) sq. units
C. \(\frac{16}{3}\) sq. units
D. \(\frac{32}{3}\) sq. units
Official Solution
Correct Answer: \(\frac{16}{3}\) sq. units
Explanation:
The area (\(A\)) of the region enclosed by the curve \(y = f(x)\), the \(x\)-axis, and the vertical lines \(x=a\) and \(x=b\) is given by the definite integral:\[A = \int_{a}^{b} f(x) dx\]
\[A = \int_{0}^{4} x^{1/2} dx\]
\[A = \frac{2}{3} \left[ x^{3/2} \right]_{0}^{4}\]
\[A = \frac{2}{3} \left[ (4)^{3/2} - (0)^{3/2} \right]\]
\[A = \frac{16}{3}\]
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