ID: Class: 12 Subject: Math Topic: Three Dimensional Geometry Type: Long (LA) Year: 2025

Question:

Find the shortest distance between the lines: \(\frac{x+1}{2}=\frac{y-1}{1}=\frac{z-9}{-3}\) and \(\frac{x-3}{2}=\frac{y+15}{-7}=\frac{z-9}{5}\).